Jika 3log (x2+1) = 3log5, maka x sama dengan

[tex]3 log( {x}^{2} + 1 ) = 3 log5 \\ {x}^{2} + 1 = 5 \\ {x}^{2} = 4 \\ x = +/-2[/tex]
Maaf kalo salah, semoga membantu

3 log (x² + 1) = 3 log 5
x² + 1 = 5
x² - 4 = 0
(x-2) (x+2) = 0
x1 = 2
x2 = -2

Jadi x = ±2