[tex]jawab[/tex][tex]1[/tex][tex]sampai[/tex][tex]5[/tex] [tex]pakai[/tex][tex]cara[/tex]

1][
3m² - 5m - 2 = 0
(3m + 1)(m - 2) = 0
m = -1/3 atau m = 2

2][
3^x + 3^2x = 90
3^2x + 3^x - 90 = 0
(3^x + 10)(3^x - 9) = 0

Yg memenuhi :
3^x - 9 = 0
x = 2

3^(x - 1) = 3^(2 - 1) = 3

3][
²log (²log (2^(x+1) + 3)) = 1 + ²log x
²log (2^(x+1) + 3) = 2x
2^(x+1) + 3 = 2^2x
2^2x - 2 . 2^x - 3 = 0
(2^x - 3)(2^x + 1) = 0
2^x - 3 = 0
2^x = 3
x = ²log 3

4][
243^(3/5) . 3^-3
= 3^5.3/5 . 3^-3
= 3^3 . 3^-3
= 1

5][
3^(x - 3) = 3^3
x - 3 = 3
x = 6