Jika dF(x) / dx = 3x^2 + 4x - 1 , maka tentukan F(x) jika F(x) = 5 di x = 2 Tolong bantu

f(x) = integral df/dx
f(x) = integaral (3x^2+4x -1) dx
f x) = 3x^(2+1)/(2+1) +4x^(1+1)/(1+1) - x + c
f (x) = x^3+2x^2-x + c
f (2) = 5
2^3 + 2.2^2-2+c = 5
8 + 8-2+c = 5
14 + c = 5
c = 5-14
c = -9
maka f(x) = x^3 +2x^2 - x -9