1.2x+y=6 x-y=-3 2.x+y=3 x-y=1 tolong bantu dengan caranya.

1. 2x+y= 6|x1→ 2x+2y=6
x-y= -3|x2→ 2x-2y = -6
---------------- -
4y = 12
y=12/4
y=3
jadi 2x+3= 6
2x= 6+3
2x= 8
x=8/2
x=4
HS={(4,3)}

2. x+y=3 |x1 →x+y= 3
x-y=1 |x1 →x-y= 1
----------- -
y = 2

jadi x+y= 3
x+2= 3
x=3+2
x=5

HS={(5,2)}

1. 2x+y =6 di kali 1 2x + 1 y= 6
x-y= -3di kali 2 2x-2y=-6
di kurangi
2x+y=6 3y=12
2x+(4)=6 y=12 \3
2x=6-4 y=4
x=2\2 =1

2. x+y=3 dikali 1 1x +1y= 3
x-y=1 dikali 1 1x - 1y= 1
di kurangin
x+y =3 2y=2
x+(1)=3 y=2\2=1
x= 3-1 = 2: