Matematika

Pertanyaan

tentukan gradien garis yang melalui titik.

a.(-1,0) dan (3,4)
b.(2,-4) dan (-1,6)
c.(4,2) dan (15,26)
d.(3,-5) dan (4,-3)

tolong jawab ya kak
makasih

2 Jawaban

  • a. 4-0/3-(-1) =4/4
    =1
    b. 6-(-4)/-1-2 =10/-3
    =3,333
  • a.
    [tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{4 - ( 0)}{3 - (-1)} \\ m = \frac{4}{4} [/tex]

    b.
    [tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{6 - ( - 4)}{ - 1 - 2} \\ m = \frac{9}{ - 3} \\ m = - 3[/tex]
    c.
    [tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{26 - 2}{15 - 4} \\ m = \frac{24}{11} \\ m = 2 \frac{2}{11} [/tex]
    d.
    [tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{ - 3 - ( - 5)}{4 - 3} \\ m = \frac{2}{1} [/tex]

    semoga membantu

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