nilai 3 integral 1 (sin 2x+3 cos x)dx =

jawab

₁³∫ (sin 2x + 3 cos x) dx

= [- 1/2 cos 2x + 3 sin x ]³₁
= - 1/2 ( cos 6x - cos 2x )  + 3 (sin 3x - sin x )

= -1/2 {- 2sin 1/2 (6x + 2x) sin 1/2 (6x -2x) +3{2 cos 1/2 (3x+x) cos 1/2(3x-x)}
= - 1/2 (-2 sin 4x sin 2x) + 3(2 cos 2x cos x)
= sin 4x sin 2x + 6 cos 2x cos x