(4)^1/2+2x - 24(2)^2x-1 = 32

jawab

(4)^(1/2 +2x)  -  24 (2)^(2x-1) - 32 = 0
(2^2)^(1/2 + 2x) - 24 (2)^(2x-1) - 32  = 0
(2)¹⁺⁴ˣ  - 24(2)ˣ⁻¹ - 32= 0
2. 2⁴ˣ . - 24. 2⁻¹ . (2)²ˣ - 32  =0
2 (2²ˣ)²  - 12 (2)²ˣ - 32 =0
(2²ˣ)² -  6 (2)²ˣ - 16= 0

2²ˣ = a, a > 0

a² - 6a - 16 = 0
(a - 8)(a + 2)  =0
a= 8 atau a = - 2 (tm)

2²ˣ = 8 = 2³
2x = 3
x = 3/2