jumlah liam suku pertama sebuah barisan geometri 2.046.jika rasio barisan tersebut 4,nilai u6

Sn = a(r^n - 1)/(r - 1)
S5 = a(4^5 - 1)/(4 - 1) = 2046
a = 6
Un = ar^(n-1)
U6 = 6.6^5 = 46656

r = 4
S5 = a(r^n-1) / r-1
2.046 = a(4^5 - 1) / 4-1
2.046 = a(1.024 - 1) / 3
2.046 = a (1.023 ) / 3
2.046 = a (341)
2.046 / 341 = a
6  = a


U6 = a.r^n-1
u6 = 6.4^6-1
u6 = 6.4^5
u6 = 6.1024
u6 = 6144