tolong bantu pr saya

Nomor 4.
A. -6x² + 19x - 15

= (2x-3) (-3x+5)
= 6x² + 10x - (-9x) - 15
= 6x²+19x-15

Nomor 6.
D. (x-8) (x-12)

= (-8+-12) = -20
= (-8x-12) = 96
= x2(-12x-8x)+96
= x2-20x+96

Maaf kalo salah

(2x - 3)(-3x + 5)
2x × -3x= -6x2
-3 × -3= 9x
2x × 5= 10x
-3 × 5= -15
jadi
-6x2 + 9x + 10x -15 =
kan 9x + 10x sama suku jadi bisa di tambahkan 19x
= A. -6x2 + 19x - 15