jika diketahui = log 2 = 0,301 log 3 = 0,477 dan log 5 = 0.699 maka nilai log 40 = Please beserta caranya

log(40)
= log(2³*5)
= log(2³) + log(5)
= 3log(2) + log(5)
= 3(0,301) + 0,699
= 0,903 + 0,699
= 1,602

Kelas 10 Matematika
Bab 1 - Pangkat, Akar dan Logaritma

^ = pangkat

log 40 = log (8 . 5)
log 40 = log 8 + log 5
log 40 = log 2^3 + log 5
log 40 = 3 . log 2 + log 5
log 40 = 3 . 0,301 + 0,699
log 40 = 0,903 + 0,699
log 40 = 1,602