diketahui trapesium abcd dan efgh sebangun. luas trapesium aefg adalah

[tex] \frac{18}{18 + 6} = \frac{ ga}{5 + ga} \\ \frac{18}{24} = \frac{ga}{5 + ga} \\ 18(5 + ga) = 24 \times ga \\ 90 + 18ga = 24ga \\ 90 = 24ga - 18ga \\ 9 0 = 6ga \\ \frac{90}{6} = \frac{6ga}{6} \\ 15 = ga \\ ga = 15 \: cm \\ \\ \frac{gf}{16} = \frac{15}{15 + 5} \\ \frac{gf}{16} = \frac{15}{20} \\ gf \times 20 = 16 \times 15 \\ 20gf = 240 \\ gf = 12 \\ \\ luas \: trapesium \: AEFG \\ = \frac{1}{2} \times (a + b) \times t \\ = \frac{1}{2} \times (gf + ae) \times ga \\ = \frac{1}{2} \times (12 + 18) \times 15 \\ = \frac{1}{2} \times 30 \times 15 \\ = 225 \: {cm}^{2} [/tex]

jadi jawabannya B
..smoga membantuu:D