Matematika

Pertanyaan

Diketahui suatu pemetaan dengan (g o f)(x) = 3x^2 - 6x + 7 dan g(x) = 3x + 1, maka f(x) =

1 Jawaban

  • (g o f) (x) = 3x² - 6x + 7
    g(f(x)) = 3x² - 6x + 7
    3f(x) + 1 = 3x² - 6x + 7
    3 f(x) = 3x² - 6x + 7 - 1
    f(x) = (3x² - 6x + 6) : 3
    f(x) = x² - 2x + 2

    komentar

    (f o g) (x) = 3x² + 5x - 6
    f(g(x)) = 3x² + 5x - 6
    3(g(x)) - 4 = 3x² + 5x - 6
    3(g(x)) = 3x² + 5x - 6 + 4
    3(g(x)) = 3x² + 5x - 2
    g(x) = (3x² + 5x - 2) : 3
    atau
    g(x) = (x² + 5/3x - 2/3)

    komentar 2

    (f o g) (x) = x² + 2x - 5
    f(g(x)) = x² + 2x - 5
    f(x - 3) = x² + 2x - 5
    misal x - 3 = p maka x = p + 3
    f(p) = (p + 3)² + 2(p + 3) - 5
    f(p) = p² + 6p + 9 + 2p + 6 - 5
    f(p) = p² + 8p + 10
    f(x) = x² + 8x + 10

    komentar 3

    f(x) = (3x + 7) / (5x - 2)
    y = (3x + 7) / (5x - 2)
    y (5x - 2) = 3x + 7
    5xy - 2y = 3x + 7
    5xy - 3x = 7 + 2y
    x (5y - 3) = 7 + 2y
    x = (7 + 2y) / (5y - 3)
    f(x)-¹ = (7 + 2x) / (5x - 3)

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