Jika f(x)=2x-1, g(x)=x^2+2, dan h(x)=1/x-1, komposisi fungsi (g°h°f)(x)=

Fungsi Komposisi

f(x) = 2x - 1
g(x) = x² + 2
h(x) = 1/(x - 1)

(gohof)(x)
= (1/(2x - 1 - 1))² + 2
= 1/(2x - 2)² + 2
= (1 + 2(2x - 2)²) / (2x - 2)²
= (1 + 8x² - 16x + 8) / (4x² - 8x + 4)
= (8x² - 16x + 9) / (4x² - 8x + 4)