1. 2 dadu homogen bersisi 6,dilempar secara bersamaan sebanyak 36 kali.Tentukan frekuensi harapan munculnya kedua mata dadu sama! 2. 3 buah mata uang logam dile

1.
A = muncul dadu sama
A = {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}
n(A) = 6
n(S) = 36
N = 36 kali
Fh = P(A) . N
Fh = n(A)/n(S) . N
Fh = 6/36 . 36
Fh = 6 kali

2.
A = muncul tepat 2 angka
A = {(AAG),(AGA),(GAA)}--->n(A) = 3
n(S) = 2^3 = 8
N = 40 kali
Fh = P(A) . N
Fh = n(A)/n(S) . N
Fh = 3/8 . 40
Fh = 15 kali