fungsi h dirumuskan dengan h(x) = px + q. jika h(2) = 1 dan h (4) = 5, maka nilai dari h (10) = ... a. 17 b. 19 c. 21 d. 23

h(x) = px + q
h(2) = 1
2p+q=1
h (4) = 5
4p+q=5
cara eliminasi
4p+q=5
2p+q=1 --->dikurang
2p=4
p=2
2p+q=1
4+q=1
q=-3
h(10)=10p+q
h(10)=20+(-3)
h(10)=17

h(x) = px + q

h(2) = 2p + q
h(2) = 1
2p + q = 1 ---> (i)

h(4) = 4p + q
h(4) = 5
4p + q = 5 ---> (ii)

Eliminasi (ii) - (i)
2p = 4
p = 2

2p + q = 1
2.2 + q = 1
4 + q = 1
q = -3

h(10) = 2.10 + (-3) = 17