perasamaan garis yang melalui titik (2,-7) dan tegak lurus garis 4x - 3y +8 =0 adalah... a. 3x + 4y = -22 b. 3x - 4y = 34 c. 4x + 3y = -13 d. 4x - 3y = 21

m1 = -a/b
m1 = -4/-3
m1 = 4/3
m1 × m2 = -1
4/3 × m2 = -1
m2 = -1/4/3
m2 = -1 × ¾
m2 = -¾
y - y1 = m(x - x1)
y - (-7) = -¾(x - 2)
y + 7 = -¾(x - 2)
4(y + 7) = -3(x - 2)
4y + 28 = -3x + 6
4y + 3x = 6 - 28
3x + 4y = -22
jawabannya adalah A