bantu tentang logaritma..........

Logaritma

[tex] ^x \log 2 + ^x \log (3x - 4) = 2 \\ ^x \log (2(3x-4)) = ^x \log x^2 \\\\ 6x - 8 = x^2 \\ x^2 - 6x + 8 = 0 \\\\ x_1 + x_2 = -\dfrac{b}{a} \\\\ x_1 + x_2 = - \dfrac{-6}{1} \\\\ x_1 + x_2 = 6 [/tex]