jika diketahui ^2log a+^2log b =12 dan 3^2log a-^2log b=4 maka a+b=.............

²log a + ²log b = 12
²log b = 12 - ²log a

3 ²log a - ²log b = 4
3 ²log a - (12- ²log a) = 4
3 ²log a + ² log a - 12 = 4
4 ²log a = 4 + 12
4 ²log a = 16
² log a = 16/4
²log a = 4
a = 2⁴
a = 16

²log b = 12 - ²log a
²log b = 12 - 4
²log b = 8
b = 2^8
b = 256

a+b=16+256=272