Matematika

Pertanyaan

pleaseeeee...help me
pleaseeeee...help me

1 Jawaban

  • [tex] {(x -a) }^{2} + {(y - b)}^{2} = {r}^{2} \\ {(x - ( - 2)}^{2} + {(y - 3)}^{2} = {5}^{2} \\ {(x + 2)}^{2} + {(y - 3)}^{2} = 25 \\ {x}^{2} + 2x + 2x + 4 + {y}^{2} - 3y - 3y + 9 = 25 \\ {x}^{2} + 4x + 13 + {y}^{2} - 6y = 25 \\ {x}^{2} + {y}^{2} + 4x - 6y - 12 = 0 \: (B)[/tex]
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